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If (a_n=11n-5), what is (k) for (a_{4k}-a_k=198)?

Answer and explanation

Correct answer: 6

Given \(a_n=11n-5\), we have \(a_{4k}=11(4k)-5=44k-5\) and \(a_k=11k-5\). Therefore, \(a_{4k}-a_k=(44k-5)-(11k-5)=33k\). From \(33k=198\), we get \(k=6\). For example, if \(k=5\), the difference would be only 165, not 198. Exam tip: Substitute each index separately in the nth-term formula before subtracting.

Related tags

Arithmetic ProgressionNth TermIndex SubstitutionAlgebraic EquationsClass 10 MathematicsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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