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In an AP, (a_{15}=0) and (a_{37}=-154). What is (a_1)?एक समान्तर श्रेणी में (a_{15}=0) और (a_{37}=-154) है। (a_1) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 9898
For an AP, \(a_{37}-a_{15}=(37-15)d\). Thus, \(-154-0=22d\), so \(d=-7\). Now, using \(a_{15}=a_1+14d\), we get \(0=a_1+14(-7)\), hence \(a_1=98\). If 84 were chosen, the 15th term would not be 0. Exam tip: Find \(d\) first by subtracting the two given terms.समान्तर श्रेणी में \(a_{37}-a_{15}=(37-15)d\)। अतः \(-154-0=22d\), इसलिए \(d=-7\)। अब \(a_{15}=a_1+14d\) से \(0=a_1+14(-7)\), इसलिए \(a_1=98\)। विकल्प 84 लेने पर 15वाँ पद 0 नहीं बनेगा। परीक्षा टिप: दो दिए गए पदों का अंतर लेकर पहले \(d\) ज्ञात करें।
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