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If \(a_n=5n+s\) and \(a_{18}=112\), what is \(a_{46}\)?यदि \(a_n=5n+s\) और \(a_{18}=112\) है तो \(a_{46}\) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(252\)\(252\)
Given \(a_n=5n+s\), we have \(a_{18}=5\times18+s=90+s\). Since \(a_{18}=112\), \(s=22\). Therefore, \(a_{46}=5\times46+22=230+22=252\). Option \(247\) would result from incorrectly taking 27 gaps; actually, \(46-18=28\). Exam tip: You may also use \(a_{46}=a_{18}+(46-18)d\), where \(d=5\).दिया है \(a_n=5n+s\)। अतः \(a_{18}=5\times18+s=90+s\)। क्योंकि \(a_{18}=112\), इसलिए \(s=22\)। अब \(a_{46}=5\times46+22=230+22=252\)। विकल्प \(247\) तब मिलता यदि पदों के बीच अंतर \(27\) लिया जाता, जबकि \(46-18=28\) है। परीक्षा टिप: दो पदों के लिए सीधे \(a_{46}=a_{18}+(46-18)d\) भी उपयोग कर सकते हैं, जहाँ \(d=5\)।
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