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In an arithmetic progression (AP), a₁₄ = 3a₆ + 5 and a₆ = 23. What is a₃₀?एक समांतर श्रेणी में a₁₄ = 3a₆ + 5 और a₆ = 23 है। a₃₀ का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 176176
First, a₁₄ = 3 × 23 + 5 = 74. Since a₁₄ − a₆ = 74 − 23 = 51 across 8 steps, the common difference is d = 51/8. From a₁₄ to a₃₀ there are 16 steps, so a₃₀ = 74 + 16 × (51/8) = 176.पहले, a₁₄ = 3 × 23 + 5 = 74। a₆ से a₁₄ तक 8 चरणों में अंतर 74 − 23 = 51 है, इसलिए सार्व अंतर d = 51/8 है। a₁₄ से a₃₀ तक 16 चरण हैं, अतः a₃₀ = 74 + 16 × (51/8) = 176।
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