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If \(a_{14}=3a_6+4\) and \(a_6=22\), what is \(a_{22}\)?

Answer and explanation

Correct answer: \(118\)

Given \(a_6=22\), we get \(a_{14}=3(22)+4=70\). In an AP, \(a_{14}-a_6=(14-6)d=8d\). Hence, \(70-22=8d\), so \(d=6\). Now \(a_{22}=a_6+(22-6)d=22+16\times6=118\). Therefore, the correct answer is \(118\). The option \(114\) results from not applying the correct difference in term numbers. Exam tip: use \(a_m-a_n=(m-n)d\) when two terms of an AP are known.

Related tags

Arithmetic ProgressionNth TermCommon DifferenceClass 10 MathematicsAp Word ProblemsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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