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In an AP, (a_1=52) and (d=-4). What is the first (n) for which (a_n) is negative?

Answer and explanation

Correct answer: 15

The nth term of an AP is \(a_n=a_1+(n-1)d\). Thus, \(a_n=52+(n-1)(-4)=56-4n\). For a negative term, \(56-4n<0\), so \(n>14\). The smallest integer satisfying this is \(n=15\), and hence \(a_{15}=-4\) is the first negative term. At \(n=14\), the term is \(0\), which is not negative. Exam tip: when the question asks for the “first” term, choose the smallest integer greater than the value obtained from the inequality.

Related tags

Arithmetic ProgressionNth TermNegative TermsInequalitiesClass 10 MathematicsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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