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If in an AP (a_3+a_9=72), what is the value of (a_6)?

Answer and explanation

Correct answer: 36

In an AP, the sum of terms equidistant from a middle term equals twice that middle term. Since the index 6 lies midway between 3 and 9, \(a_3+a_9=2a_6\). Thus, \(2a_6=72\), so \(a_6=36\). Values such as 34 or 38 would not give the stated sum of 72. Exam tip: use \(a_{m-r}+a_{m+r}=2a_m\) for symmetric terms in an AP.

Related tags

Arithmetic ProgressionNth TermMiddle TermSymmetric TermsClass 10 MathematicsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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