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In an AP, (a_8=27) and (a_{18}=77). Which term will be (152)?

Answer and explanation

Correct answer: 33rd term

Given \(a_8=27\) and \(a_{18}=77\), the common difference is \(d=\frac{77-27}{18-8}=5\). Using \(a_n=a_8+(n-8)d\), we get \(152=27+(n-8)\times5\). Thus, \(125=5(n-8)\), so \(n-8=25\) and \(n=33\). Hence, 152 is the 33rd term. The 32nd term would be \(147\), so it is not correct. Exam tip: When two terms are given, first find \(d\) using the difference in their term numbers.

Related tags

Arithmetic ProgressionNth TermCommon DifferenceLinear SequenceClass 10 MathematicsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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