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In an arithmetic progression (AP), a₂ₘ = 58, aₘ = 31, and the common difference d = 3. What is the value of m?किसी समानांतर श्रेणी (AP) में a₂ₘ = 58, aₘ = 31 और सार्व अंतर d = 3 है। m का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 99
The index difference between a₂ₘ and aₘ is 2m − m = m, so a₂ₘ − aₘ = md. Thus 58 − 31 = 3m, giving 27 = 3m and m = 9.a₂ₘ और aₘ के सूचकांकों का अंतर 2m − m = m है, इसलिए a₂ₘ − aₘ = md। अतः 58 − 31 = 3m, यानी 27 = 3m और m = 9।
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