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In an AP (a_{10}=58) and (a_{22}=130). What is the first term?एक AP में (a_{10}=58) और (a_{22}=130) है। पहला पद क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 44
For an AP, \(a_n=a+(n-1)d\). Thus, \(a_{22}-a_{10}=12d=130-58=72\), so \(d=6\). Now \(a_{10}=a+9d\) gives \(58=a+9\times6\), hence \(a=4\). Option 6 is the common difference, not the first term. Exam tip: When two terms are given, first use the difference in their term numbers to find \(d\).AP में \(a_n=a+(n-1)d\) होता है। अतः \(a_{22}-a_{10}=12d=130-58=72\), इसलिए \(d=6\)। अब \(a_{10}=a+9d\) से \(58=a+9\times6\), अतः \(a=4\)। विकल्प 6 सामान्य अंतर है, पहला पद नहीं। परीक्षा टिप: दो दिए हुए पदों के क्रमांकों का अंतर लेकर पहले \(d\) ज्ञात करें।
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