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In an AP, if a₉ = 52 and a₁₇ = 108, what is a₂₅?एक समान्तर श्रेणी में यदि a₉ = 52 और a₁₇ = 108 है, तो a₂₅ क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 164164
There are 17 − 9 = 8 steps between a₉ and a₁₇, so the common difference is d = (108 − 52)/8 = 7. There are also 25 − 17 = 8 steps from a₁₇ to a₂₅, so a₂₅ = 108 + 8 × 7 = 164.a₉ और a₁₇ के बीच 17 − 9 = 8 चरण हैं, इसलिए सार्व अंतर d = (108 − 52)/8 = 7 है। a₁₇ से a₂₅ तक भी 25 − 17 = 8 चरण हैं, अतः a₂₅ = 108 + 8 × 7 = 164।
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