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The (14)th term of an AP is (92) and (d=7). What is (a_1)?

Answer and explanation

Correct answer: \(1\)

For an AP, \(a_n=a_1+(n-1)d\). Thus, \(92=a_1+(14-1)\times7=a_1+91\), so \(a_1=1\). Option \(85\) would result from subtracting \(d\) only once, but moving from the 14th term to the first term requires subtracting \(13d\). Exam tip: always use \(n-1\) in the formula for the \(n\)th term.

Related tags

Arithmetic ProgressionNth TermFirst TermCommon DifferenceClass 10 MathematicsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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