In an AP, a₆ = 38 and a₁₅ = 101. What is a₂₄?एक समान्तर श्रेणी में a₆ = 38 और a₁₅ = 101 है। a₂₄ का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 164164
The 9 steps from the 6th to the 15th term increase the value by 101 − 38 = 63, so the common difference is 63 ÷ 9 = 7. From the 15th to the 24th term is another 9 steps; therefore, a₂₄ = 101 + 9 × 7 = 164.छठे से 15वें पद तक 9 चरणों में मान 101 − 38 = 63 बढ़ता है, इसलिए सार्व अंतर 63 ÷ 9 = 7 है। 15वें से 24वें पद तक भी 9 चरण हैं; अतः a₂₄ = 101 + 9 × 7 = 164।
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