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If in an AP (a_6+a_{14}=100), what is the value of (a_{10})?यदि किसी समान्तर श्रेणी में (a_6+a_{14}=100) है तो (a_{10}) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (50)(50)
(a_{10}) is the middle term between (a_6) and (a_{14}), so (a_{10}=\frac{100}{2}=50). The average of equally spaced terms is the middle term.(a_6) और (a_{14}) के बीच का पद (a_{10}) है इसलिए (a_{10}=\frac{100}{2}=50)। समान दूरी वाले पदों का औसत बीच वाला पद होता है।
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