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If (a_9=42) and (a_{16}=77), what is (a_{23})?

Answer and explanation

Correct answer: (112)

The direct answer is D, 112. First find the common difference using the two known terms: \(a_{16}-a_9=77-42=35\), and there are \(16-9=7\) steps, so \(d=35/7=5\). The 23rd term is seven steps after the 16th term. Therefore \(a_{23}=77+7(5)=77+35=112\). Option A, 105, adds only 28 and is one step short. Option B, 108, does not follow the common difference of 5. Option C, 110, is also not obtained by seven increases of 5. Option D, 112, is correct. The important idea is that equally spaced terms in an AP have equal increases: from position 9 to 16 and from 16 to 23, both movements contain seven steps. Count steps between indices rather than counting terms themselves.

Related tags

ApTwo-Known-TermsNth-TermClass10

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