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A theatre has (18) seats in the first row and each next row has (2) more seats. How many seats are in the (20)th row?

Answer and explanation

Correct answer: 56

This forms an arithmetic progression with first term \(a=18\), common difference \(d=2\), and \(n=20\). Using \(a_n=a+(n-1)d\), \(a_{20}=18+(20-1)\times2=18+38=56\). Therefore, the 20th row has 56 seats. Choosing 58 would result from incorrectly adding the difference one extra time. Exam tip: in the \(n\)th term, the common difference is added \(n-1\) times.

Related tags

Arithmetic ProgressionNth TermAp Word ProblemSeating ArrangementClass 10 MathematicsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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