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In a savings plan, (₹200) is deposited in the first week and (₹50) more is deposited each week. What is the deposit in the (15)th week?

Answer and explanation

Correct answer: (₹900)

The direct answer is B, ₹900. The weekly deposits form an arithmetic progression: the first deposit is \(a=₹200\), the common increase is \(d=₹50\), and the required term is the 15th term. Use \(a_n=a+(n-1)d\): \(a_{15}=200+(15-1)50=200+14\times50=200+700=₹900\). Option A, ₹850, is one weekly increase too small. Option B, ₹900, correctly gives the deposit made in week 15. Option C, ₹950, adds 15 increases instead of 14, forgetting that the first week already starts at ₹200. Option D, ₹1000, adds still more than the required increases. The question asks for one week’s deposit, not the total saved over fifteen weeks. The exam cue is to count the increases between week 1 and week n as \(n-1\), not n.

Related tags

ApWord-ProblemSavingsNth-Term

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