What is the (40)th term of the AP (\frac{1}{2},1,\frac{3}{2},\ldots)?समान्तर श्रेणी (\frac{1}{2},1,\frac{3}{2},\ldots) का (40)वां पद क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (20)(20)
Here (a=\frac{1}{2}), (d=\frac{1}{2}), so (a_{40}=\frac{1}{2}+39\cdot\frac{1}{2}=20). Fractions can also be checked as decimals.यहां (a=\frac{1}{2}), (d=\frac{1}{2}), इसलिए (a_{40}=\frac{1}{2}+39\cdot\frac{1}{2}=20)। भिन्नों को दशमलव में बदलकर भी जांच सकते हैं।
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