If (a_2=10) and (d=4), what is the (6)th term?

Correct answer: (26)

In an arithmetic progression, moving from the rth term to the nth term requires n-r equal steps, each of size d. Here the given term is a_2=10, the required term is a_6, and d=4. The number of steps is 6-2=4, so a_6=a_2+(6-2)d=10+4(4)=10+16=26. Therefore option C is correct. A common mistake is to add only three differences or to use six differences, which would produce distractors such as 22 or 34. The formula a_n=a_r+(n-r)d avoids that indexing error and uses the supplied second term directly.