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In a school hall, the first row has 12 chairs and each next row has 3 more chairs. How many chairs will be in the 15th row?

Answer and explanation

Correct answer: 54

The row counts form an arithmetic progression because every successive row increases by the same number, 3. The first term is a = 12, the common difference is d = 3, and the required row number is n = 15. Apply aₙ = a + (n − 1)d: a₁₅ = 12 + (15 − 1)×3 = 12 + 14×3 = 12 + 42 = 54. Therefore option B is correct. In this context, the row number corresponds to the term number. Option A uses only thirteen or fewer increases, option C adds one extra increase, and option D contradicts the exact calculation. The sequence begins 12, 15, 18 and reaches 54 at the fifteenth term.

Related tags

Arithmetic ProgressionWord ProblemNth TermFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)Arithmetic Progressions ApMathematics

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