यदि (p(x)=x-3-x) है तो ग्राफ (x)-अक्ष को किन (x)-मानों पर मिल सकता है?
If (p(x)=x-3-x), at which (x)-values can the graph meet the (x)-axis?
Explanation opens after your attempt
Correct Answer
A. (-1), (0), (1)
Concept
(x-3-x=x(x-1)(x+1)), so the zeroes are (-1), (0), (1). Tip: factor out the common term first.
Why this answer is correct
The correct answer is A. (-1), (0), (1). (x-3-x=x(x-1)(x+1)), so the zeroes are (-1), (0), (1). Tip: factor out the common term first.
Exam Tip
(x-3-x=x(x-1)(x+1)) इसलिए शून्यक (-1), (0), (1) हैं। टिप: पहले सामान्य गुणनखंड निकालें।
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