Concept-wise Practice

case-counting MCQ Questions for Class 11

case-counting se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

1 questions tagged with case-counting.

यदि \(A=\{1,2,3,4,5\}\) है, तो (\mathcal{P}(A)) में (2) और (3) दोनों को साथ-साथ रखने या दोनों को न रखने वाले subsets कितने हैं?

If \(A=\{1,2,3,4,5\}\), how many subsets in (\mathcal{P}(A)) either contain both (2) and (3) or contain neither of them?

Explanation opens after your attempt
Correct Answer

B. (16)

Step 1

Concept

For the pair ({2,3}), there are (2) choices and for the remaining (3) elements there are \(2^3\), so \(2\cdot2^3=16\). In exams, split linked elements into cases.

Step 2

Why this answer is correct

The correct answer is B. (16). For the pair ({2,3}), there are (2) choices and for the remaining (3) elements there are \(2^3\), so \(2\cdot2^3=16\). In exams, split linked elements into cases.

Step 3

Exam Tip

जोड़ी ({2,3}) के लिए (2) choices हैं और बाकी (3) तत्वों के लिए \(2^3\), इसलिए \(2\cdot2^3=16\)। परीक्षा में linked elements को cases में बांटें।

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