एक किरण पहले \(\frac{17\pi}{6}\) वामावर्त और फिर \(\frac{5\pi}{3}\) दक्षिणावर्त घूमती है। अंतिम मुख्य कोण क्या है?
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Correct Answer
B. \(\frac{7\pi}{6}\)
Concept
The net angle is \(\frac{17\pi}{6}-\frac{5\pi}{3}=\frac{7\pi}{6}\). Take counterclockwise as positive and clockwise as negative.
Why this answer is correct
The correct answer is B. \(\frac{7\pi}{6}\). The net angle is \(\frac{17\pi}{6}-\frac{5\pi}{3}=\frac{7\pi}{6}\). Take counterclockwise as positive and clockwise as negative.
Exam Tip
नेट कोण \(\frac{17\pi}{6}-\frac{5\pi}{3}=\frac{7\pi}{6}\) है। वामावर्त को धनात्मक और दक्षिणावर्त को ऋणात्मक लें।
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