Hard Mathematics Polynomials Class 10 Level 25

कौन सा विकल्प (\(\sqrt{2}+\sqrt{5}+\sqrt{8}\)) का सरल रूप है?

Which option is the simplified form of (\(\sqrt{2}+\sqrt{5}+\sqrt{8}\))?

Explanation opens after your attempt
Correct Answer

A. \(3\sqrt{2}+\sqrt{5}\)

Step 1

Concept

\(\sqrt{8}=2\sqrt{2}\), so \(\sqrt{2}+\sqrt{8}=3\sqrt{2}\). The unlike root \(\sqrt{5}\) remains separate.

Step 2

Why this answer is correct

The correct answer is A. \(3\sqrt{2}+\sqrt{5}\). \(\sqrt{8}=2\sqrt{2}\), so \(\sqrt{2}+\sqrt{8}=3\sqrt{2}\). The unlike root \(\sqrt{5}\) remains separate.

Step 3

Exam Tip

\(\sqrt{8}=2\sqrt{2}\) इसलिए \(\sqrt{2}+\sqrt{8}=3\sqrt{2}\) होता है। असमान जड़ \(\sqrt{5}\) अलग रहती है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प (\(\sqrt{2}+\sqrt{5}+\sqrt{8}\)) का सरल रूप है? / Which option is the simplified form of (\(\sqrt{2}+\sqrt{5}+\sqrt{8}\))?

Correct Answer: A. \(3\sqrt{2}+\sqrt{5}\). Explanation: \(\sqrt{8}=2\sqrt{2}\) इसलिए \(\sqrt{2}+\sqrt{8}=3\sqrt{2}\) होता है। असमान जड़ \(\sqrt{5}\) अलग रहती है। / \(\sqrt{8}=2\sqrt{2}\), so \(\sqrt{2}+\sqrt{8}=3\sqrt{2}\). The unlike root \(\sqrt{5}\) remains separate.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{8}=2\sqrt{2}\), so \(\sqrt{2}+\sqrt{8}=3\sqrt{2}\). The unlike root \(\sqrt{5}\) remains separate.

What exam hint can help solve this Mathematics question?

\(\sqrt{8}=2\sqrt{2}\) इसलिए \(\sqrt{2}+\sqrt{8}=3\sqrt{2}\) होता है। असमान जड़ \(\sqrt{5}\) अलग रहती है।

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