Medium Mathematics Polynomials Class 10 Level 25

कौन सा विकल्प \(\sqrt{162}\) का सरल रूप है?

Which option is the simplified form of \(\sqrt{162}\)?

Explanation opens after your attempt
Correct Answer

A. \(9\sqrt{2}\)

Step 1

Concept

\(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\). Take the greatest perfect square inside the root.

Step 2

Why this answer is correct

The correct answer is A. \(9\sqrt{2}\). \(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\). Take the greatest perfect square inside the root.

Step 3

Exam Tip

\(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\) है। जड़ में सबसे बड़ा पूर्ण वर्ग लें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प \(\sqrt{162}\) का सरल रूप है? / Which option is the simplified form of \(\sqrt{162}\)?

Correct Answer: A. \(9\sqrt{2}\). Explanation: \(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\) है। जड़ में सबसे बड़ा पूर्ण वर्ग लें। / \(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\). Take the greatest perfect square inside the root.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\). Take the greatest perfect square inside the root.

What exam hint can help solve this Mathematics question?

\(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\) है। जड़ में सबसे बड़ा पूर्ण वर्ग लें।

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