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What is the value of (a-b+c) for \(2x^2-3x-5=0\)?
A. (0)
Here (a=2), (b=-3), (c=-5). Thus (a-b+c=2-(-3)-5=0).
The correct answer is A. (0). Here (a=2), (b=-3), (c=-5). Thus (a-b+c=2-(-3)-5=0).
यहां (a=2), (b=-3), (c=-5) हैं। इसलिए (a-b+c=2-(-3)-5=0) है।
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Correct Answer: A. (0). Explanation: यहां (a=2), (b=-3), (c=-5) हैं। इसलिए (a-b+c=2-(-3)-5=0) है। / Here (a=2), (b=-3), (c=-5). Thus (a-b+c=2-(-3)-5=0).
Here (a=2), (b=-3), (c=-5). Thus (a-b+c=2-(-3)-5=0).
यहां (a=2), (b=-3), (c=-5) हैं। इसलिए (a-b+c=2-(-3)-5=0) है।
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