समीकरण \(4x^2-13x+9=0\) के मूलों के व्युत्क्रमों का योग क्या है?
What is the sum of reciprocals of the roots of \(4x^2-13x+9=0\)?
Explanation opens after your attempt
Correct Answer
A. \( \frac{13}{9} \)
Concept
The sum of reciprocals is \(\frac{\alpha+\beta}{\alpha\beta}\). Here it is \(\frac{\frac{13}{4}}{\frac{9}{4}}=\frac{13}{9}\).
Why this answer is correct
The correct answer is A. \( \frac{13}{9} \). The sum of reciprocals is \(\frac{\alpha+\beta}{\alpha\beta}\). Here it is \(\frac{\frac{13}{4}}{\frac{9}{4}}=\frac{13}{9}\).
Exam Tip
व्युत्क्रमों का योग \(\frac{\alpha+\beta}{\alpha\beta}\) होता है। यहाँ \(\frac{\frac{13}{4}}{\frac{9}{4}}=\frac{13}{9}\) है।
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