Medium Mathematics Permutations and Combinations Class 11 Level 62

\(\binom{9}{4}+\binom{9}{5}\) पास्कल पहचान से किसके बराबर है?

Using Pascal's identity \(\binom{9}{4}+\binom{9}{5}\) is equal to which expression?

Explanation opens after your attempt
Correct Answer

A. \(\binom{10}{5}\)

Step 1

Concept

By Pascal's identity \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\). Hence the answer is \(\binom{10}{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(\binom{10}{5}\). By Pascal's identity \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\). Hence the answer is \(\binom{10}{5}\).

Step 3

Exam Tip

पास्कल पहचान से \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\) होता है। इसलिए उत्तर \(\binom{10}{5}\) है।

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Mathematics Answer, Explanation and Revision Hints

\(\binom{9}{4}+\binom{9}{5}\) पास्कल पहचान से किसके बराबर है? / Using Pascal's identity \(\binom{9}{4}+\binom{9}{5}\) is equal to which expression?

Correct Answer: A. \(\binom{10}{5}\). Explanation: पास्कल पहचान से \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\) होता है। इसलिए उत्तर \(\binom{10}{5}\) है। / By Pascal's identity \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\). Hence the answer is \(\binom{10}{5}\).

Which concept should I revise for this Mathematics MCQ?

By Pascal's identity \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\). Hence the answer is \(\binom{10}{5}\).

What exam hint can help solve this Mathematics question?

पास्कल पहचान से \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\) होता है। इसलिए उत्तर \(\binom{10}{5}\) है।

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