Expert Mathematics Quadratic Equations Class 10 Level 30

समीकरण \(x^2-9x+4=0\) के मूल \(\alpha,\beta\) हैं। \(\alpha+\beta+5\alpha\beta\) का मान क्या है?

The roots of \(x^2-9x+4=0\) are \(\alpha,\beta\). What is \(\alpha+\beta+5\alpha\beta\)?

Explanation opens after your attempt
Correct Answer

A. (29)

Step 1

Concept

The sum of roots is (9) and the product is (4). Therefore \(\alpha+\beta+5\alpha\beta=9+20=29\).

Step 2

Why this answer is correct

The correct answer is A. (29). The sum of roots is (9) and the product is (4). Therefore \(\alpha+\beta+5\alpha\beta=9+20=29\).

Step 3

Exam Tip

मूलों का योग (9) और गुणनफल (4) है। इसलिए \(\alpha+\beta+5\alpha\beta=9+20=29\)।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(x^2-9x+4=0\) के मूल \(\alpha,\beta\) हैं। \(\alpha+\beta+5\alpha\beta\) का मान क्या है? / The roots of \(x^2-9x+4=0\) are \(\alpha,\beta\). What is \(\alpha+\beta+5\alpha\beta\)?

Correct Answer: A. (29). Explanation: मूलों का योग (9) और गुणनफल (4) है। इसलिए \(\alpha+\beta+5\alpha\beta=9+20=29\)। / The sum of roots is (9) and the product is (4). Therefore \(\alpha+\beta+5\alpha\beta=9+20=29\).

Which concept should I revise for this Mathematics MCQ?

The sum of roots is (9) and the product is (4). Therefore \(\alpha+\beta+5\alpha\beta=9+20=29\).

What exam hint can help solve this Mathematics question?

मूलों का योग (9) और गुणनफल (4) है। इसलिए \(\alpha+\beta+5\alpha\beta=9+20=29\)।

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