Expert Mathematics Quadratic Equations Class 10 Level 29

समीकरण \(x^2-8x+5=0\) के मूल \(\alpha,\beta\) हैं। \(\alpha+\beta+4\alpha\beta\) का मान क्या है?

The roots of \(x^2-8x+5=0\) are \(\alpha,\beta\). What is \(\alpha+\beta+4\alpha\beta\)?

Explanation opens after your attempt
Correct Answer

A. (28)

Step 1

Concept

The sum of roots is (8) and the product is (5). Therefore \(\alpha+\beta+4\alpha\beta=8+20=28\).

Step 2

Why this answer is correct

The correct answer is A. (28). The sum of roots is (8) and the product is (5). Therefore \(\alpha+\beta+4\alpha\beta=8+20=28\).

Step 3

Exam Tip

मूलों का योग (8) और गुणनफल (5) है। इसलिए \(\alpha+\beta+4\alpha\beta=8+20=28\)।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(x^2-8x+5=0\) के मूल \(\alpha,\beta\) हैं। \(\alpha+\beta+4\alpha\beta\) का मान क्या है? / The roots of \(x^2-8x+5=0\) are \(\alpha,\beta\). What is \(\alpha+\beta+4\alpha\beta\)?

Correct Answer: A. (28). Explanation: मूलों का योग (8) और गुणनफल (5) है। इसलिए \(\alpha+\beta+4\alpha\beta=8+20=28\)। / The sum of roots is (8) and the product is (5). Therefore \(\alpha+\beta+4\alpha\beta=8+20=28\).

Which concept should I revise for this Mathematics MCQ?

The sum of roots is (8) and the product is (5). Therefore \(\alpha+\beta+4\alpha\beta=8+20=28\).

What exam hint can help solve this Mathematics question?

मूलों का योग (8) और गुणनफल (5) है। इसलिए \(\alpha+\beta+4\alpha\beta=8+20=28\)।

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