Expert Mathematics Quadratic Equations Class 10 Level 28

समीकरण \(x^2-7x+3=0\) के मूल \(\alpha,\beta\) हैं। \(\alpha+\beta+3\alpha\beta\) का मान क्या है?

The roots of \(x^2-7x+3=0\) are \(\alpha,\beta\). What is \(\alpha+\beta+3\alpha\beta\)?

Explanation opens after your attempt
Correct Answer

A. (16)

Step 1

Concept

The sum of roots is (7) and the product is (3). Therefore \(\alpha+\beta+3\alpha\beta=7+9=16\).

Step 2

Why this answer is correct

The correct answer is A. (16). The sum of roots is (7) and the product is (3). Therefore \(\alpha+\beta+3\alpha\beta=7+9=16\).

Step 3

Exam Tip

मूलों का योग (7) और गुणनफल (3) है। इसलिए \(\alpha+\beta+3\alpha\beta=7+9=16\)।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(x^2-7x+3=0\) के मूल \(\alpha,\beta\) हैं। \(\alpha+\beta+3\alpha\beta\) का मान क्या है? / The roots of \(x^2-7x+3=0\) are \(\alpha,\beta\). What is \(\alpha+\beta+3\alpha\beta\)?

Correct Answer: A. (16). Explanation: मूलों का योग (7) और गुणनफल (3) है। इसलिए \(\alpha+\beta+3\alpha\beta=7+9=16\)। / The sum of roots is (7) and the product is (3). Therefore \(\alpha+\beta+3\alpha\beta=7+9=16\).

Which concept should I revise for this Mathematics MCQ?

The sum of roots is (7) and the product is (3). Therefore \(\alpha+\beta+3\alpha\beta=7+9=16\).

What exam hint can help solve this Mathematics question?

मूलों का योग (7) और गुणनफल (3) है। इसलिए \(\alpha+\beta+3\alpha\beta=7+9=16\)।

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