Hard Mathematics Polynomials Class 10 Level 25

यदि \(x=\sqrt{6}-\sqrt{2}\) है तो \(x^2\) का सरल रूप क्या है?

If \(x=\sqrt{6}-\sqrt{2}\), what is the simplified form of \(x^2\)?

Explanation opens after your attempt
Correct Answer

A. \(8-4\sqrt{3}\)

Step 1

Concept

(\(\sqrt{6}-\sqrt{2}\)2=6+2-2\sqrt{12}=8-4\sqrt{3}). Write the (2ab) term carefully.

Step 2

Why this answer is correct

The correct answer is A. \(8-4\sqrt{3}\). (\(\sqrt{6}-\sqrt{2}\)2=6+2-2\sqrt{12}=8-4\sqrt{3}). Write the (2ab) term carefully.

Step 3

Exam Tip

(\(\sqrt{6}-\sqrt{2}\)2=6+2-2\sqrt{12}=8-4\sqrt{3}) है। (2ab) पद ध्यान से लिखें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{6}-\sqrt{2}\) है तो \(x^2\) का सरल रूप क्या है? / If \(x=\sqrt{6}-\sqrt{2}\), what is the simplified form of \(x^2\)?

Correct Answer: A. \(8-4\sqrt{3}\). Explanation: (\(\sqrt{6}-\sqrt{2}\)2=6+2-2\sqrt{12}=8-4\sqrt{3}) है। (2ab) पद ध्यान से लिखें। / (\(\sqrt{6}-\sqrt{2}\)2=6+2-2\sqrt{12}=8-4\sqrt{3}). Write the (2ab) term carefully.

Which concept should I revise for this Mathematics MCQ?

(\(\sqrt{6}-\sqrt{2}\)2=6+2-2\sqrt{12}=8-4\sqrt{3}). Write the (2ab) term carefully.

What exam hint can help solve this Mathematics question?

(\(\sqrt{6}-\sqrt{2}\)2=6+2-2\sqrt{12}=8-4\sqrt{3}) है। (2ab) पद ध्यान से लिखें।

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