यदि \(x=\frac{5}{2}\) समीकरण \(2x^2-9x+c=0\) का मूल है तो (c) का मान क्या है?
If \(x=\frac{5}{2}\) is a root of \(2x^2-9x+c=0\), what is the value of (c)?
Explanation opens after your attempt
Correct Answer
A. (10)
Concept
Putting \(x=\frac{5}{2}\) gives \(\frac{25}{2}-\frac{45}{2}+c=0\), so (c=10). Calculate each term carefully with a fractional root.
Why this answer is correct
The correct answer is A. (10). Putting \(x=\frac{5}{2}\) gives \(\frac{25}{2}-\frac{45}{2}+c=0\), so (c=10). Calculate each term carefully with a fractional root.
Exam Tip
\(x=\frac{5}{2}\) रखने पर \(\frac{25}{2}-\frac{45}{2}+c=0\) इसलिए (c=10) है। भिन्न मूल में हर पद सावधानी से निकालें।
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