यदि \(x=\frac{4}{3}\) समीकरण \(3x^2-7x+c=0\) का मूल है तो (c) का मान क्या है?
If \(x=\frac{4}{3}\) is a root of \(3x^2-7x+c=0\), what is the value of (c)?
Explanation opens after your attempt
Correct Answer
A. (4)
Concept
Putting \(x=\frac{4}{3}\) gives \(\frac{16}{3}-\frac{28}{3}+c=0\), so (c=4). For fractional roots calculate each term separately.
Why this answer is correct
The correct answer is A. (4). Putting \(x=\frac{4}{3}\) gives \(\frac{16}{3}-\frac{28}{3}+c=0\), so (c=4). For fractional roots calculate each term separately.
Exam Tip
\(x=\frac{4}{3}\) रखने पर \(\frac{16}{3}-\frac{28}{3}+c=0\) इसलिए (c=4) है। भिन्न मूल में हर पद अलग निकालें।
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