यदि \(x=\frac{3}{2}\) समीकरण \(2x^2-5x+c=0\) का मूल है तो (c) का मान क्या है?
If \(x=\frac{3}{2}\) is a root of \(2x^2-5x+c=0\), what is the value of (c)?
Explanation opens after your attempt
Correct Answer
A. (3)
Concept
Putting \(x=\frac{3}{2}\) gives \(\frac{9}{2}-\frac{15}{2}+c=0\), so (c=3). For fractional roots calculate each term separately.
Why this answer is correct
The correct answer is A. (3). Putting \(x=\frac{3}{2}\) gives \(\frac{9}{2}-\frac{15}{2}+c=0\), so (c=3). For fractional roots calculate each term separately.
Exam Tip
\(x=\frac{3}{2}\) रखने पर \(\frac{9}{2}-\frac{15}{2}+c=0\) इसलिए (c=3) है। भिन्न मूल में हर पद अलग निकालें।
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