यदि \(x=\frac{1}{2}\) समीकरण \(4x^2+px-3=0\) का मूल है तो (p) का मान क्या है?
If \(x=\frac{1}{2}\) is a root of \(4x^2+px-3=0\), what is the value of (p)?
Explanation opens after your attempt
Correct Answer
B. (4)
Concept
Putting \(x=\frac{1}{2}\) gives \(1+\frac{p}{2}-3=0\), so (p=4). When substituting a fractional root, solve each term carefully.
Why this answer is correct
The correct answer is B. (4). Putting \(x=\frac{1}{2}\) gives \(1+\frac{p}{2}-3=0\), so (p=4). When substituting a fractional root, solve each term carefully.
Exam Tip
\(x=\frac{1}{2}\) रखने पर \(1+\frac{p}{2}-3=0\) इसलिए (p=4)। भिन्न मूल रखते समय हर पद सावधानी से हल करें।
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