यदि \(x^2-2ax+a^2-36=0\) है, तो मूलों का अंतर क्या होगा?
If \(x^2-2ax+a^2-36=0\), what will be the difference of the roots?
Explanation opens after your attempt
Correct Answer
A. (12)
Concept
The equation is ((x-a)2-36=0), so the roots are (a+6) and (a-6). Their difference is (12).
Why this answer is correct
The correct answer is A. (12). The equation is ((x-a)2-36=0), so the roots are (a+6) and (a-6). Their difference is (12).
Exam Tip
समीकरण ((x-a)2-36=0) है, इसलिए मूल (a+6) और (a-6) हैं। उनका अंतर (12) है।
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