Medium Mathematics Quadratic Equations Class 10 Level 29

यदि \(x^2+sx+18=0\) के मूल (-3) और (-6) हैं, तो (s) का मान क्या है?

If the roots of \(x^2+sx+18=0\) are (-3) and (-6), what is the value of (s)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

The sum of roots is (-9), and in \(x^2+sx+18=0\) the sum is (-s). Therefore (s=9).

Step 2

Why this answer is correct

The correct answer is A. (9). The sum of roots is (-9), and in \(x^2+sx+18=0\) the sum is (-s). Therefore (s=9).

Step 3

Exam Tip

मूलों का योग (-9) है और \(x^2+sx+18=0\) में योग (-s) होता है। इसलिए (s=9) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2+sx+18=0\) के मूल (-3) और (-6) हैं, तो (s) का मान क्या है? / If the roots of \(x^2+sx+18=0\) are (-3) and (-6), what is the value of (s)?

Correct Answer: A. (9). Explanation: मूलों का योग (-9) है और \(x^2+sx+18=0\) में योग (-s) होता है। इसलिए (s=9) है। / The sum of roots is (-9), and in \(x^2+sx+18=0\) the sum is (-s). Therefore (s=9).

Which concept should I revise for this Mathematics MCQ?

The sum of roots is (-9), and in \(x^2+sx+18=0\) the sum is (-s). Therefore (s=9).

What exam hint can help solve this Mathematics question?

मूलों का योग (-9) है और \(x^2+sx+18=0\) में योग (-s) होता है। इसलिए (s=9) है।

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