यदि (x-2-(2k+5)x+\(k^2+5k+6\)=0) के मूल लगातार पूर्णांक हैं, तो वे मूल कौन-से होंगे?
If the roots of (x-2-(2k+5)x+\(k^2+5k+6\)=0) are consecutive integers, what will those roots be?
Explanation opens after your attempt
Correct Answer
A. (k+2) और (k+3)(k+2) and (k+3)
Concept
The sum of roots is (2k+5) and the product is \(k^2+5k+6\). ((k+2)+(k+3)=2k+5) and ((k+2)(k+3)=k-2+5k+6) are correct.
Why this answer is correct
The correct answer is A. (k+2) और (k+3) / (k+2) and (k+3). The sum of roots is (2k+5) and the product is \(k^2+5k+6\). ((k+2)+(k+3)=2k+5) and ((k+2)(k+3)=k-2+5k+6) are correct.
Exam Tip
मूलों का योग (2k+5) और गुणनफल \(k^2+5k+6\) है। ((k+2)+(k+3)=2k+5) और ((k+2)(k+3)=k-2+5k+6) सही है।
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