यदि (p(x)=x-2+px+q) का ग्राफ (x)-अक्ष को ((-2,0)) और ((5,0)) पर काटता है, तो (p) और (q) के मान क्या होंगे?
If the graph of (p(x)=x-2+px+q) cuts the (x)-axis at ((-2,0)) and ((5,0)), what will be the values of (p) and (q)?
Explanation opens after your attempt
A. (p=-3, q=-10)
Concept
The zeroes are (-2) and (5), so the polynomial is ((x+2)(x-5)=x-2-3x-10). Tip: form factors from graph intersections.
Why this answer is correct
The correct answer is A. (p=-3, q=-10). The zeroes are (-2) and (5), so the polynomial is ((x+2)(x-5)=x-2-3x-10). Tip: form factors from graph intersections.
Exam Tip
शून्यक (-2) और (5) हैं, इसलिए बहुपद ((x+2)(x-5)=x-2-3x-10) है। टिप: ग्राफ कटान से गुणनखंड बनाएं।
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