यदि (p(x)=x-2+1) है तो इसका ग्राफ (x)-अक्ष को क्यों नहीं काटता?
If (p(x)=x-2+1), why does its graph not cut the (x)-axis?
Explanation opens after your attempt
Correct Answer
A. क्योंकि \(x^2+1\) हमेशा धनात्मक हैBecause \(x^2+1\) is always positive
Concept
For real (x), \(x^2\geq0\), so \(x^2+1>0\). Tip: if (p(x)) never becomes (0), there is no intersection.
Why this answer is correct
The correct answer is A. क्योंकि \(x^2+1\) हमेशा धनात्मक है / Because \(x^2+1\) is always positive. For real (x), \(x^2\geq0\), so \(x^2+1>0\). Tip: if (p(x)) never becomes (0), there is no intersection.
Exam Tip
वास्तविक (x) के लिए \(x^2\geq0\) इसलिए \(x^2+1>0\) है। टिप: (p(x)) कभी (0) न हो तो कटान नहीं होगा।
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