यदि ((k+1)x-2-5x+6=0) एक द्विघात समीकरण है, तो (k) पर सही शर्त क्या है?
If ((k+1)x-2-5x+6=0) is a quadratic equation, what is the correct condition on (k)?
Explanation opens after your attempt
B. \(k\neq -1\)
Concept
For a quadratic equation, the coefficient of \(x^2\) must not be (0). Thus \(k+1\neq 0\), so \(k\neq -1\).
Why this answer is correct
The correct answer is B. \(k\neq -1\). For a quadratic equation, the coefficient of \(x^2\) must not be (0). Thus \(k+1\neq 0\), so \(k\neq -1\).
Exam Tip
द्विघात होने के लिए \(x^2\) का गुणांक (0) नहीं होना चाहिए। इसलिए \(k+1\neq 0\), अर्थात \(k\neq -1\)।
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