Medium Mathematics Quadratic Equations Class 10 Level 28

यदि ((k+1)x-2-5x+6=0) एक द्विघात समीकरण है, तो (k) पर सही शर्त क्या है?

If ((k+1)x-2-5x+6=0) is a quadratic equation, what is the correct condition on (k)?

Explanation opens after your attempt
Correct Answer

B. \(k\neq -1\)

Step 1

Concept

For a quadratic equation, the coefficient of \(x^2\) must not be (0). Thus \(k+1\neq 0\), so \(k\neq -1\).

Step 2

Why this answer is correct

The correct answer is B. \(k\neq -1\). For a quadratic equation, the coefficient of \(x^2\) must not be (0). Thus \(k+1\neq 0\), so \(k\neq -1\).

Step 3

Exam Tip

द्विघात होने के लिए \(x^2\) का गुणांक (0) नहीं होना चाहिए। इसलिए \(k+1\neq 0\), अर्थात \(k\neq -1\)।

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Mathematics Answer, Explanation and Revision Hints

यदि ((k+1)x-2-5x+6=0) एक द्विघात समीकरण है, तो (k) पर सही शर्त क्या है? / If ((k+1)x-2-5x+6=0) is a quadratic equation, what is the correct condition on (k)?

Correct Answer: B. \(k\neq -1\). Explanation: द्विघात होने के लिए \(x^2\) का गुणांक (0) नहीं होना चाहिए। इसलिए \(k+1\neq 0\), अर्थात \(k\neq -1\)। / For a quadratic equation, the coefficient of \(x^2\) must not be (0). Thus \(k+1\neq 0\), so \(k\neq -1\).

Which concept should I revise for this Mathematics MCQ?

For a quadratic equation, the coefficient of \(x^2\) must not be (0). Thus \(k+1\neq 0\), so \(k\neq -1\).

What exam hint can help solve this Mathematics question?

द्विघात होने के लिए \(x^2\) का गुणांक (0) नहीं होना चाहिए। इसलिए \(k+1\neq 0\), अर्थात \(k\neq -1\)।

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