Hard Mathematics Quadratic Equations Class 10 Level 29

यदि \(2x^2+kx+18=0\) में मूलों का गुणनफल मूलों के योग का (-3) गुना है, तो (k) क्या होगा?

If in \(2x^2+kx+18=0\), the product of roots is (-3) times the sum of roots, what is (k)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

The product is (9) and the sum is \(-\frac{k}{2}\). From (9=-3\left\(-\frac{k}{2}\right\)), we get (k=6).

Step 2

Why this answer is correct

The correct answer is A. (6). The product is (9) and the sum is \(-\frac{k}{2}\). From (9=-3\left\(-\frac{k}{2}\right\)), we get (k=6).

Step 3

Exam Tip

गुणनफल (9) और योग \(-\frac{k}{2}\) है। (9=-3\left\(-\frac{k}{2}\right\)) से (k=6) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(2x^2+kx+18=0\) में मूलों का गुणनफल मूलों के योग का (-3) गुना है, तो (k) क्या होगा? / If in \(2x^2+kx+18=0\), the product of roots is (-3) times the sum of roots, what is (k)?

Correct Answer: A. (6). Explanation: गुणनफल (9) और योग \(-\frac{k}{2}\) है। (9=-3\left\(-\frac{k}{2}\right\)) से (k=6) मिलता है। / The product is (9) and the sum is \(-\frac{k}{2}\). From (9=-3\left\(-\frac{k}{2}\right\)), we get (k=6).

Which concept should I revise for this Mathematics MCQ?

The product is (9) and the sum is \(-\frac{k}{2}\). From (9=-3\left\(-\frac{k}{2}\right\)), we get (k=6).

What exam hint can help solve this Mathematics question?

गुणनफल (9) और योग \(-\frac{k}{2}\) है। (9=-3\left\(-\frac{k}{2}\right\)) से (k=6) मिलता है।

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