Expert Mathematics Quadratic Equations Class 10 Level 33

यदि \(4x^2-12x+5=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^3+\beta^3\) का सही मान क्या है?

If \(\alpha,\beta\) are the roots of \(4x^2-12x+5=0\), what is the correct value of \(\alpha^3+\beta^3\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{63}{4}\)

Step 1

Concept

Here \(\alpha+\beta=3\) and \(\alpha\beta=\frac{5}{4}\). Thus \(\alpha^3+\beta^3=27-\frac{45}{4}=\frac{63}{4}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{63}{4}\). Here \(\alpha+\beta=3\) and \(\alpha\beta=\frac{5}{4}\). Thus \(\alpha^3+\beta^3=27-\frac{45}{4}=\frac{63}{4}\).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=3\) और \(\alpha\beta=\frac{5}{4}\) है। \(\alpha^3+\beta^3=27-\frac{45}{4}=\frac{63}{4}\)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(4x^2-12x+5=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^3+\beta^3\) का सही मान क्या है? / If \(\alpha,\beta\) are the roots of \(4x^2-12x+5=0\), what is the correct value of \(\alpha^3+\beta^3\)?

Correct Answer: A. \(\frac{63}{4}\). Explanation: यहाँ \(\alpha+\beta=3\) और \(\alpha\beta=\frac{5}{4}\) है। \(\alpha^3+\beta^3=27-\frac{45}{4}=\frac{63}{4}\)। / Here \(\alpha+\beta=3\) and \(\alpha\beta=\frac{5}{4}\). Thus \(\alpha^3+\beta^3=27-\frac{45}{4}=\frac{63}{4}\).

Which concept should I revise for this Mathematics MCQ?

Here \(\alpha+\beta=3\) and \(\alpha\beta=\frac{5}{4}\). Thus \(\alpha^3+\beta^3=27-\frac{45}{4}=\frac{63}{4}\).

What exam hint can help solve this Mathematics question?

यहाँ \(\alpha+\beta=3\) और \(\alpha\beta=\frac{5}{4}\) है। \(\alpha^3+\beta^3=27-\frac{45}{4}=\frac{63}{4}\)।

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