यदि \(3x^2-8x+4=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^3+\beta^3\) का मान क्या है?
If \(\alpha,\beta\) are the roots of \(3x^2-8x+4=0\), what is \(\alpha^3+\beta^3\)?
Explanation opens after your attempt
Correct Answer
B. \(\frac{224}{27}\)
Concept
Here \(\alpha+\beta=\frac{8}{3}\) and \(\alpha\beta=\frac{4}{3}\). Using (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)), we get \(\frac{224}{27}\).
Why this answer is correct
The correct answer is B. \(\frac{224}{27}\). Here \(\alpha+\beta=\frac{8}{3}\) and \(\alpha\beta=\frac{4}{3}\). Using (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)), we get \(\frac{224}{27}\).
Exam Tip
यहाँ \(\alpha+\beta=\frac{8}{3}\) और \(\alpha\beta=\frac{4}{3}\) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)) से \(\frac{224}{27}\) मिलता है।
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