यदि \(x^2-7x+10=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^2-6\alpha+\beta^2-6\beta\) का सही मान क्या है?
If \(\alpha,\beta\) are roots of \(x^2-7x+10=0\), what is the correct value of \(\alpha^2-6\alpha+\beta^2-6\beta\)?
Explanation opens after your attempt
Correct Answer
A. (-13)
Concept
(\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=49-20=29). Therefore the value is (29-6\(\alpha+\beta\)=29-42=-13).
Why this answer is correct
The correct answer is A. (-13). (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=49-20=29). Therefore the value is (29-6\(\alpha+\beta\)=29-42=-13).
Exam Tip
(\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=49-20=29) है। इसलिए मान (29-6\(\alpha+\beta\)=29-42=-13) है।
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