Expert Mathematics Quadratic Equations Class 10 Level 31

यदि \(x^2+5x+r=0\) की जड़ें \(\alpha,\beta\) हैं और \(\alpha^2\beta+\alpha\beta^2=-20\), तो (r) क्या है?

If \(\alpha,\beta\) are roots of \(x^2+5x+r=0\) and \(\alpha^2\beta+\alpha\beta^2=-20\), what is (r)?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

We use (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)). Here \(\alpha+\beta=-5\), so (r(-5)=-20) and (r=4).

Step 2

Why this answer is correct

The correct answer is A. (4). We use (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)). Here \(\alpha+\beta=-5\), so (r(-5)=-20) and (r=4).

Step 3

Exam Tip

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)) होता है। यहाँ \(\alpha+\beta=-5\), इसलिए (r(-5)=-20) और (r=4)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2+5x+r=0\) की जड़ें \(\alpha,\beta\) हैं और \(\alpha^2\beta+\alpha\beta^2=-20\), तो (r) क्या है? / If \(\alpha,\beta\) are roots of \(x^2+5x+r=0\) and \(\alpha^2\beta+\alpha\beta^2=-20\), what is (r)?

Correct Answer: A. (4). Explanation: (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)) होता है। यहाँ \(\alpha+\beta=-5\), इसलिए (r(-5)=-20) और (r=4)। / We use (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)). Here \(\alpha+\beta=-5\), so (r(-5)=-20) and (r=4).

Which concept should I revise for this Mathematics MCQ?

We use (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)). Here \(\alpha+\beta=-5\), so (r(-5)=-20) and (r=4).

What exam hint can help solve this Mathematics question?

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)) होता है। यहाँ \(\alpha+\beta=-5\), इसलिए (r(-5)=-20) और (r=4)।

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