यदि \(x^2-4x-12=0\) की जड़ें \(\alpha,\beta\) हैं, तो (\(\alpha-5\)\(\beta-5\)) का मान क्या है?
If \(\alpha,\beta\) are roots of \(x^2-4x-12=0\), what is (\(\alpha-5\)\(\beta-5\))?
Explanation opens after your attempt
Correct Answer
A. (-7)
Concept
We use (\(\alpha-5\)\(\beta-5\)=\alpha\beta-5\(\alpha+\beta\)+25). Since \(\alpha+\beta=4\) and \(\alpha\beta=-12\), the value is (-7).
Why this answer is correct
The correct answer is A. (-7). We use (\(\alpha-5\)\(\beta-5\)=\alpha\beta-5\(\alpha+\beta\)+25). Since \(\alpha+\beta=4\) and \(\alpha\beta=-12\), the value is (-7).
Exam Tip
(\(\alpha-5\)\(\beta-5\)=\alpha\beta-5\(\alpha+\beta\)+25) है। \(\alpha+\beta=4\) और \(\alpha\beta=-12\), इसलिए मान (-7) है।
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