यदि \(x^2-17x+72=0\) के मूल \(\alpha,\beta\) हैं, तो \(\frac{1}{\alpha}+\frac{1}{\beta}\) क्या है?
If \(\alpha,\beta\) are roots of \(x^2-17x+72=0\), what is \(\frac{1}{\alpha}+\frac{1}{\beta}\)?
Explanation opens after your attempt
Correct Answer
A. \( \frac{17}{72} \)
Concept
\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}\). Here the value is \(\frac{17}{72}\).
Why this answer is correct
The correct answer is A. \( \frac{17}{72} \). \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}\). Here the value is \(\frac{17}{72}\).
Exam Tip
\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}\) होता है। यहाँ मान \(\frac{17}{72}\) है।
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