यदि \(x^2-10x+21=0\) के मूल \(\alpha,\beta\) हैं, तो (\(\alpha-3\)\(\beta-3\)) का मान क्या है?
If \(\alpha,\beta\) are roots of \(x^2-10x+21=0\), what is (\(\alpha-3\)\(\beta-3\))?
Explanation opens after your attempt
A. (0)
Concept
(\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9). Here (21-30+9=0).
Why this answer is correct
The correct answer is A. (0). (\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9). Here (21-30+9=0).
Exam Tip
(\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9) है। यहाँ (21-30+9=0)।
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