Hard Mathematics Quadratic Equations Class 10 Level 29

यदि \(x^2-10x+21=0\) के मूल \(\alpha,\beta\) हैं, तो (\(\alpha-3\)\(\beta-3\)) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-10x+21=0\), what is (\(\alpha-3\)\(\beta-3\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9). Here (21-30+9=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9). Here (21-30+9=0).

Step 3

Exam Tip

(\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9) है। यहाँ (21-30+9=0)।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-10x+21=0\) के मूल \(\alpha,\beta\) हैं, तो (\(\alpha-3\)\(\beta-3\)) का मान क्या है? / If \(\alpha,\beta\) are roots of \(x^2-10x+21=0\), what is (\(\alpha-3\)\(\beta-3\))?

Correct Answer: A. (0). Explanation: (\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9) है। यहाँ (21-30+9=0)। / (\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9). Here (21-30+9=0).

Which concept should I revise for this Mathematics MCQ?

(\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9). Here (21-30+9=0).

What exam hint can help solve this Mathematics question?

(\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9) है। यहाँ (21-30+9=0)।

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